shorthand c++ if else statement

Question

So I\'m just curious if there is a short hand statement to this:

if(number < 0 )
  bigInt.sign = 0;
else
  bigInt.sign = 1;

I see all th

Answer 1

The basic syntax for using ternary operator is like this:

(condition) ? (if_true) : (if_false)

For you case it is like this:

number < 0 ? bigInt.sign = 0 : bigInt.sign = 1;

Answer 2

try this:

bigInt.sign = number < 0 ? 0 : 1

Answer 3

Yes:

bigInt.sign = !(number < 0);

The ! operator always evaluates to true or false. When converted to int, these become 1 and 0 respectively.

Of course this is equivalent to:

bigInt.sign = (number >= 0);

Here the parentheses are redundant but I add them for clarity. All of the comparison and relational operator evaluate to true or false.

Answer 4

Depending on how often you use this in your code you could consider the following:

macro

#define SIGN(x) ( (x) >= 0 )

Inline function

inline int sign(int x)
{
    return x >= 0;
}

Then you would just go:

bigInt.sign = sign(number);