Java BigDecimal remove decimal and trailing numbers

Question

I\'m new to Java and trying to take a BigDecimal (for example 99999999.99) and convert it to a string but without the decimal place and trailing numbers. Also, I don\'t want

Answer 1

Use this.

BigDecimal truncated= number.setScale(0,BigDecimal.ROUND_DOWN);

Answer 2

Try number.toBigInteger().toString()

Answer 3

BigDecimal without fractions is BigInteger. Why don't you just use BigInteger?

Answer 4

private void showDoubleNo(double n) {
    double num = n; 
    int decimalPlace = 2; 
    BigDecimal bd = new BigDecimal(num); 
    bd = bd.setScale(decimalPlace,BigDecimal.ROUND_UP); 
    System.out.println("Point is "+bd); 
}

Answer 5

public static String convertBigDecimalToString(BigDecimal bg) {
      System.out.println("Big Decimal Value before its convertion :" + bg.setScale(2, BigDecimal.ROUND_HALF_UP));

      String bigDecStringValue = bg.setScale(0,BigDecimal.ROUND_HALF_UP).toPlainString();

      System.out.println("Big Decimal String Value after removing Decimal places is :" + bigDecStringValue);

      return bigDecStringValue;
}

Please note : I have used 'BigDecimal.ROUND_HALF_UP' , just to make sure, Rounding mode to round towards "nearest neighbor" unless both neighbors are equidistant

Answer 6

Here's the most elegant way I found to resolve this:

public static String convertDecimalToString (BigDecimal num){
    String ret = null;
    try {
        ret = num.toBigIntegerExact().toString();
    } catch (ArithmeticException e){
        num = num.setScale(2,BigDecimal.ROUND_UP); 
        ret = num.toPlainString();
    }
    return ret;
}