Property 'self.*' not initialized at super.init call

Question

I just updated my xcode to 6.3.1. The problem is I got this weird error message since Swift 1.2. I got this kind of error message

/Users/MNurdin/Documents/iO         


        

Answer 1

You have to initialize all property before you call super.init in any init method

So,change this before you call super.init()

originView = sourceView //error here

Exception:

1. optional property
2. property with default value
3. lazy property

Answer 2

From Apple's “The Swift Programming Language” book:

“Swift’s compiler performs four helpful safety-checks to make sure that two-phase initialization is completed without error”

“A designated initializer must ensure that all of the “properties introduced by its class are initialized before it delegates up to a superclass initializer.”

Basically you have to ensure that your instance variables are in a consistent state before you do anything, including calling methods.

class YourClass {
    var view: UIView
    init(view: UIView) {
        self.view = view
    }
}

well in your case you can make it a new UIView:

let originView = UIView()

or make it nullable

let originView: UIView?

or make a lazy property instead:

lazy var originView: UIView = {
    let view = UIView(frame: CGRect(x: 0, y: 0, width: 375, height: 200))
    // customize it
    return view
}()

when using lazy instantiation you can pass a method:

lazy var originView: UIView = self.createView()

func createView() -> UIView {
    let view = UIView(frame: CGRect(x: 0, y: 0, width: 375, height: 200))
        // customize it
        return view
}

Answer 3

Make your originView nullable by

var originView: UIView?. 

If your originView is not nullable you have to provide a default value before calling

super.init().