java.math.BigInteger cannot be cast to java.lang.Long

Question

I\'ve got List dynamics. And I want to get max result using Collections. This is my code:

List dynamics=spy         


        

Answer 1

You need to add an alias for the count to your query and then use the addScalar() method as the default for list() method in Hibernate seams to be BigInteger for numeric SQL types. Here is an example:

List<Long> sqlResult = session.createSQLQuery("SELECT column AS num FROM table")
    .addScalar("num", StandardBasicTypes.LONG).list();

Answer 2

It's a very old post, but if it benefits anyone, we can do something like this:

Long max=((BigInteger) Collections.max(dynamics)).longValue(); 

Answer 3

Better option is use SQLQuery#addScalar than casting to Long or BigDecimal.

Here is modified query that returns count column as Long

Query query = session
             .createSQLQuery("SELECT COUNT(*) as count
                             FROM SpyPath 
                             WHERE DATE(time)>=DATE_SUB(CURDATE(),INTERVAL 6 DAY) 
                             GROUP BY DATE(time) 
                             ORDER BY time;")
             .addScalar("count", LongType.INSTANCE);

Then

List<Long> result = query.list(); //No ClassCastException here  

Related link

• Hibernate javadocs
• Scalar queries
• Hibernate.LONG, remember it has been deprecated since Hibernate version 3.6.X
  here is the deprecated document, so you have to use LongType.INSTANCE
• My previous answer

Answer 4

I'm lacking context, but this is working just fine:

List<BigInteger> nums = new ArrayList<BigInteger>();
Long max = Collections.max(nums).longValue(); // from BigInteger to Long...

Answer 5

Are you sure dynamics is a List<Long> and not List<BigInteger> ?

If dynamics is a List<Long> you don't need to do a cast to (Long)

Answer 6

Imagine d.getId is a Long, then wrap like this:

BigInteger l  = BigInteger.valueOf(d.getId());