Drop the last item with LINQ [duplicate]

Answer 1

For .NET Core 2+ and .NET Standard 2.1 (planned), you can use .SkipLast(1).

For other platforms, you could write your own LINQ query operator (that is, an extension method on IEnumerable<T>), for example:

static IEnumerable<T> SkipLast<T>(this IEnumerable<T> source)
{
    using (var e = source.GetEnumerator())
    {
        if (e.MoveNext())
        {
            for (var value = e.Current; e.MoveNext(); value = e.Current)
            {
                yield return value;
            }
        }
    }
}

Unlike other approaches such as xs.Take(xs.Count() - 1), the above will process a sequence only once.

Answer 2

You can quite easily do this with an extension method, either using the form you've already found, or perhaps a combination of Take and Count

public static IEnumerable<T> DropLast<T>(this IEnumerable<T> enumerable)
{
  return enumerable.Take(enumerable.Count()-1);
}

Answer 3

someList.Reverse().Skip(1).Reverse()