split alpha and numeric using sql

Question

I have a table and it has a 3 columns. The first column is the data that contains value(numeric) and unit(percentage and etc..), the second col

Answer 1

change @concunit & @unitx Respectively

 DECLARE @concunit varchar(10)='45.5%'
DECLARE @unitx varchar(10)='%'

BEGIN
SELECT RTRIM(SUBSTRING( @concunit , 1 , CHARINDEX( @unitx , @concunit
                                              ) - 1
                )) AS Number, 
       RTRIM(SUBSTRING( @concunit , CHARINDEX( @unitx , @concunit
                                          ) , LEN( @concunit
                                                 ) - (CHARINDEX( @unitx , @concunit
                                                               ) - 1)
                )) AS Unit

end

Answer 2

Would something like this work? Based on the shown data it looks like it would.

Apply it to your data set as a select and if you like the results then you can make an update from it.

WITH cte as (SELECT 'ug/mL' ConcUnit, 500 as [Numeric], '' as Unit 
   UNION ALL SELECT '2000 ug/mL',     NULL,             '')

SELECT
    [ConcUnit]                  as [ConcUnit],
    [Numeric]                   as [Original Numeric],
    [Unit]                      as [Original Unit],
    CASE WHEN ConcUnit LIKE '% %' THEN 
        SUBSTRING(ConcUnit, 1, CHARINDEX(' ', ConcUnit) - 1) 
        ELSE [Numeric] END      as [New Numeric],
    CASE WHEN ConcUnit LIKE '% %' 
        THEN SUBSTRING(ConcUnit, CHARINDEX(' ', ConcUnit) + 1, LEN(ConcUnit)) 
        ELSE ConcUnit END       as [New Unit]
FROM cte

Answer 3

Here is my answer. Check output in SQLFiddle for the same.

create TABLE temp
(
      string NVARCHAR(50)
)

INSERT INTO temp (string)
VALUES 
    ('4000 ug\ml'),
    ('2000 ug\ml'),
    ('%'),
    ('ug\ml')

SELECT subsrtunit,LEFT(subsrtnumeric, PATINDEX('%[^0-9]%', subsrtnumeric+'t') - 1)
FROM (
    SELECT subsrtunit = SUBSTRING(string, posofchar, LEN(string)),
  subsrtnumeric = SUBSTRING(string, posofnumber, LEN(string))
    FROM (
        SELECT string, posofchar = PATINDEX('%[^0-9]%', string),
      posofnumber = PATINDEX('%[0-9]%', string)
        FROM temp
    ) d
) t

Updated Version to handle 99.5 ug\ml

create TABLE temp
(
      string NVARCHAR(50)
)

INSERT INTO temp (string)
VALUES 
    ('4000 ug\ml'),
    ('2000 ug\ml'),
    ('%'),
    ('ug\ml'),
    ('99.5 ug\ml')

SELECT subsrtunit,LEFT(subsrtnumeric, PATINDEX('%[^0-9.]%', subsrtnumeric+'t') - 1)
FROM (
    SELECT subsrtunit = SUBSTRING(string, posofchar, LEN(string)),
  subsrtnumeric = SUBSTRING(string, posofnumber, LEN(string))
    FROM (
        SELECT string, posofchar = PATINDEX('%[^0-9.]%', string),
      posofnumber = PATINDEX('%[0-9.]%', string)
        FROM temp
    ) d
) t

Updated Version: To handle 1 000 ug\ml,20 000ug\ml

create TABLE temp
(
      string NVARCHAR(50)
)

INSERT INTO temp (string)
VALUES 
    ('4000 ug\ml'),
    ('2000 ug\ml'),
    ('%'),
    ('ug\ml'),
    ('99.5 ug\ml'),
    ('1 000 ug\ml'),
    ('20 000ug\ml')

SELECT substring(replace(subsrtunit,' ',''),PATINDEX('%[0-9.]%', replace(subsrtunit,' ',''))+1,len(subsrtunit)),
LEFT(replace(subsrtnumeric,' ',''), PATINDEX('%[^0-9.]%', replace(subsrtnumeric,' ','')+'t') - 1)
FROM (
    SELECT subsrtunit = SUBSTRING(string, posofchar, LEN(string)),
  subsrtnumeric = SUBSTRING(string, posofnumber, LEN(string))
    FROM (
        SELECT string, posofchar = PATINDEX('%[^0-9.]%', replace(string,' ','')),
      posofnumber = PATINDEX('%[0-9.]%', replace(string,' ',''))
        FROM temp
    ) d
) t

Check out SQLFiddle for the same.

Answer 4

If the numeric part is always at the beginning, then you can use this:

PATINDEX('%[0-9][^0-9]%', ConcUnit)

to get the index of the last digit.

Thus, this:

DECLARE @str VARCHAR(MAX) = '4000 ug/ML' 

SELECT LEFT(@str, PATINDEX('%[0-9][^0-9]%', @str )) AS Number,
       LTRIM(RIGHT(@str, LEN(@str) - PATINDEX('%[0-9][^0-9]%', @str ))) As Unit

gives you:

Number  Unit
-------------
4000    ug/ML

EDIT:

If numeric data include double values as well, then you can use this:

SELECT LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))

to get the index of the last digit.

Thus, this:

SELECT LEFT(@str, LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str)))

gives you the numeric part.

And this:

SELECT LEFT(@str, LEN(@str) - PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))) AS Numeric,
       CASE 
          WHEN CHARINDEX ('%', @str) <> 0 THEN LTRIM(RIGHT(@str, LEN(@str) - CHARINDEX ('%', @str)))
          ELSE LTRIM(RIGHT(@str, PATINDEX ('%[^0-9][0-9]%', REVERSE(@str))))
       END AS Unit

gives you both numberic and unit part.

Here are some tests that I made with the data you have posted:

Input:

DECLARE @str VARCHAR(MAX) = '50 000ug/ML'

Output:

Numeric Unit
------------
50 000  ug/ML

Input:

DECLARE @str VARCHAR(MAX) = '99.5%'

Output:

Numeric Unit
------------
99.5    

Input:

DECLARE @str VARCHAR(MAX) = '4000 . 35 % ug/ML'

Output:

Numeric     Unit
------------------
4000 . 35   ug/ML