I am using CursorAdapter
and below is my adapter class. My list consists of two text views and one button on each row. Now, on click of the button I want to del
Try some thing like this :
@Override
public void bindView(View view, Context context, final Cursor cursor) {
TextView txtName = (TextView) view.findViewById(R.id.txt_name);
txtName.setText(cursor.getString(cursor.getColumnIndex(Helper
.tbl_col_username)));
TextView txtPassword = (TextView) view.findViewById(R.id.txt_password);
txtPassword.setText(cursor.getString(cursor.getColumnIndex(Helper
.tbl_col_password)));
final String itemId = cursor.getString(cursor.getColumnIndex("id"));
Button button = (Button) view.findViewById(R.id.btn_delete);
button.setOnClickListener(new OnClickListener() {
public void onClick(View arg0) {
Log.d(TAG, "Button Click ");
deleteRecordWithId(itemId);
cursor.requery();
notifyDataSetChanged();
}
});
}
Im assuming this ID is in the cursor. Then simply make your own class DeleteEntryOnClicklistener which implements OnClickListener and let it take the ID in its constructor, and deletes the entry when clicked.
Please comment if I have misunderstood your problem or if Im being unclear, cheers :)
edit:
In your bindView()
, change the OnClicklistener to something like this:
long id = cursor.getLong(cursor.getColumnIndex(Helper.tbl_col_id));
button.setOnClicklistener(new DeleteEntryOnClicklistener(id));
And DeleteEntryOnClicklistener
should look something like this:
public class DeleteEntryOnClicklistener implements View.OnClickListener {
long id;
public DeleteEntryOnClicklistener(long id) {
this.id = id;
}
@Override
public void onClick(View v) {
database.deleteEntry(id);
}
}