Combining elements of list of lists by index

Question

Consider the following list of lists:

lst = list(list(c(1,2), c(3,4)),list(c(5,6), c(7,8)),list(c(9,10), c(11,12)))

The list lst

Answer 1

I was looking for something along the lines of the OP's question... but with a list of data frames instead of vectors. In that case, slightly modifying @joran's answer above gives the desired result. Consider:

mylist <- 
  lapply(1:2, function(y){
    df1 <- data.frame(a=y, b=y^2, c=y^3)
    df2 <- data.frame(d=y, e=y+1)
    return(list(df1=df1, df2=df2))
    }) 

You can then re-combine the sub-list elements into separate data frames based on their common indexes:

library(dplyr)
mylist2 <- do.call(function(...) mapply(bind_rows, ..., SIMPLIFY=F), args = mylist)

Answer 2

You can do:

do.call(Map, c(c, lst))

Answer 3

You're on the right track:

do.call(function(...) mapply(c,...,SIMPLIFY = FALSE),args = lst)
[[1]]
[1]  1  2  5  6  9 10

[[2]]
[1]  3  4  7  8 11 12