Is there anyway to get indexOf like you would get in a string.
output.add(\"1 2 3 4 5 6 7 8 9 10);
String bigger[] = output.get(i).split(\" \");
int bigge
Use this ...
output.add("1 2 3 4 5 6 7 8 9 10");
String bigger[] = output.get(i).split(" ");
int biggerWher = Arrays.asList(bigger).indexOf("3");
When the array is an array of objects, then:
Object[] array = ..
Arrays.asList(array).indexOf(someObj);
Another alternative is org.apache.commons.lang.ArrayUtils.indexOf(...) which also has overloads for arrays of primitive types, as well as a 3 argument version that takes a starting offset. (The Apache version should be more efficient because they don't entail creating a temporary List
instance.)
Arrays do not have an indexOf()
method; however, java.util.List
does. So you can wrap your array in a list and use the List
methods (except for add()
and the like):
output.add("1 2 3 4 5 6 7 8 9 10");
String bigger[] = output.get(i).split(" ");
int biggerWhere = Arrays.asList(bigger).indexOf("10");
output.add("1 2 3 4 5 6 7 8 9 10");
you miss a "
after 10.
There is no direct indexOf method in Java arrays.
You can use java.util.Arrays.binarySearch(array, item);
That will give you an index of the item, if any...
Please note, however, that the array needs to be sorted before searching.
Regards