I\'m playing with using an SVG gradientFill as a way to visually \'truncate\' long text strings in a d3.js chart.
It seems that an external css style for fill will o
In my case it was as simple as replacing attr
with style
in the d3 chain:
.style('stroke', 'url(#gradient--min)')
Because in SVG, like HTML before it, styles trump attribute styling.
fill="red"
below is NOT an "inline style", style="fill:green"
IS an inline style.
<svg width="400" height="400">
<text x="50" y="50" fill="red" style="fill:green">This will be green</text>
</svg>
Like wise, if you have a style defined outside, it will win.
<style>
text { fill: lime; }
</style>
<svg width="300" height="300">
<text x="50" y="40" fill="red">This will be lime</text>
</svg>
From the SVG specification
For user agents that support CSS, the presentation attributes must be translated to corresponding CSS style rules according to rules described in Precedence of non-CSS presentational hints ([CSS2], section 6.4.4), with the additional clarification that the presentation attributes are conceptually inserted into a new author style sheet which is the first in the author style sheet collection. The presentation attributes thus will participate in the CSS2 cascade as if they were replaced by corresponding CSS style rules placed at the start of the author style sheet with a specificity of zero. In general, this means that the presentation attributes have lower priority than other CSS style rules specified in author style sheets or ‘style’ attributes.
So you could use an inline style rather than a presentation attribute e.g.
.attr('style', 'fill : url(#theGradient)')