How to convert an int to a little endian byte array?

Question

I have this function in C# to convert a little endian byte array to an integer number:

int LE2INT(byte[] data)
{
  return (data[3] << 24) | (data[2] &l         


        

Answer 1

Could you use the BitConverter class? It will only work on little-endian hardware I believe, but it should handle most of the heavy lifting for you.

The following is a contrived example that illustrates the use of the class:

if (BitConverter.IsLittleEndian)
{
    int someInteger = 100;
    byte[] bytes = BitConverter.GetBytes(someInteger);
    int convertedFromBytes = BitConverter.ToInt32(bytes, 0);
}

Answer 2

Just reverse it, Note that this this code (like the other) works only on a little Endian machine. (edit - that was wrong, since this code returns LE by definition)

  byte[] INT2LE(int data)
  {
     byte[] b = new byte[4];
     b[0] = (byte)data;
     b[1] = (byte)(((uint)data >> 8) & 0xFF);
     b[2] = (byte)(((uint)data >> 16) & 0xFF);
     b[3] = (byte)(((uint)data >> 24) & 0xFF);
     return b;
  }