How does Python's triple-quote string work?

Question

How should this function be changed to return \"123456\"?

def f():
    s = \"\"\"123
    456\"\"\"
    return s

UPDATE: Everyo

Answer 1

My guess is:

def f():
    s = """123
    456"""
    return u'123456'

Minimum change and does what is asked for.

Answer 2

Maybe I'm missing something obvious but what about this:

def f():
    s = """123456"""
    return s

or simply this:

def f():
    s = "123456"
    return s

or even simpler:

def f():
    return "123456"

If that doesn't answer your question, then please clarify what the question is about.

Answer 3

def f():
  s = """123\
456"""
  return s

Don't indent any of the blockquote lines after the first line; end every line except the last with a backslash.

Answer 4

re.sub('\D+', '', s)

will return a string, if you want an integer, convert this string with int.

Answer 5

textwrap.dedent("""\
                123
                456""")

From the standard library. First "\" is necessary because this function works by removing the common leading whitespace.

Answer 6

Subsequent strings are concatenated, so you can use:

def f():
    s = ("123"
         "456")
    return s

This will allow you to keep indention as you like.