Django : Filter query based on custom function

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没有蜡笔的小新 2020-12-09 08:01

I\'ve got a function built into my Django model class and I want to use that function to filter my query results.

  class service:
       ......
       def i         


        
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  • 2020-12-09 08:11

    You may not be able to, instead you can post-process the queryset with a list comprehension or generator expression.

    For example:

    [x for x in Q if x.somecond()]
    
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  • 2020-12-09 08:12

    I just had a similar issue. The problem was i had to return a QuerySet instance. A quick solution for me was to do something like:

    active_serv_ids = [service.id for service in Service.objects.all() if service.is_active()]
    nserv = Service.objects.filter(id__in=active_serv_ids)
    

    pretty sure this is not the prettiest and performant way to do this, but i works for me.

    a more verbose way of doing this would be:

    active_serv_ids = []
    
    for service in Service.objects.all():
    if service.is_active():
        active_serv_ids.append(service.id)
    
    nserv = Service.objects.filter(id__in=active_serv_ids)
    
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  • 2020-12-09 08:15

    The answer by Ignacio is interesting, but it does not return a queryset. This one does:

    def users_by_role(role):
        users = User.objects.all()
        ids = [user.id for user in users if user.role == role]
        return users.filter(id__in=ids)
    
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  • 2020-12-09 08:16

    I would suggest you to use a custom manager for your class, like this you could use :

    nserv = service.objects.are_active()

    This would be achieved with something like:

    class ServiceManager(models.Manager):
        def are_active(self):
            # use your method to filter results
            return you_custom_queryset
    

    See custom managers

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