Bash - How to call a function declared in a parent shell?

Question

I am writing a bash script that calls functions declared in the parent shell, but it doesn\'t work.

For example:

$ function myfunc() { echo \"Here in         


        

Answer 1

@OP, normally you would put your function that every script uses in a file, then you source it in your script. example, save

function myfunc() { echo "Here in myfunc" ; }

in a file called /path/library. Then in your script, source it like this:

#!/bin/bash
. /path/library
myfunc

Answer 2

Try

$ export -f myfunc

in the parent shell, to export the function.

Answer 3

This also works but I noticed ${0} takes parent's value: Maybe more useful if you don't want to have a bunch of export calls in your scripts.

script1:

#!/bin/bash

func()
{
  echo func "${1}"
}

func "1"
$(. ./script2)

script2:

#!/bin/bash

func "2"

Output:

[mymachine]# ./script1
func 1
func 2