Get argument type of template callable object

Question

Consider the following function:

template
void register_handler( F& f ) // any callable object
{
   // find out T - the argument type of f         


        

Answer 1

Assuming F is any callable type, you cannot get its argument type. Consider this:

struct callable
{
    void operator() (int);
    void operator() (float *);
    void operator() (std::string const &);
    void operator() (std::list<int> &);
};

the type of argument is an ambiguity here.

Answer 2

This blogpost shows how to implement some function type traits. These should work with everything callable (exception: polymorphic functors :P). You could iterate over the arguments, and use their type to do some sfinae or as a additional template argument.

Function traits as copied from blogpost:

#include <tuple>

// as seen on http://functionalcpp.wordpress.com/2013/08/05/function-traits/
template<class F>
struct function_traits;

// function pointer
template<class R, class... Args>
struct function_traits<R(*)(Args...)> : public function_traits<R(Args...)>
{};

template<class R, class... Args>
struct function_traits<R(Args...)>
{
    using return_type = R;

    static constexpr std::size_t arity = sizeof...(Args);

    template <std::size_t N>
    struct argument
    {
        static_assert(N < arity, "error: invalid parameter index.");
        using type = typename std::tuple_element<N,std::tuple<Args...>>::type;
    };
};

// member function pointer
template<class C, class R, class... Args>
struct function_traits<R(C::*)(Args...)> : public function_traits<R(C&,Args...)>
{};

// const member function pointer
template<class C, class R, class... Args>
struct function_traits<R(C::*)(Args...) const> : public function_traits<R(C&,Args...)>
{};

// member object pointer
template<class C, class R>
struct function_traits<R(C::*)> : public function_traits<R(C&)>
{};

// functor
template<class F>
struct function_traits
{
    private:
        using call_type = function_traits<decltype(&F::operator())>;
    public:
        using return_type = typename call_type::return_type;

        static constexpr std::size_t arity = call_type::arity - 1;

        template <std::size_t N>
        struct argument
        {
            static_assert(N < arity, "error: invalid parameter index.");
            using type = typename call_type::template argument<N+1>::type;
        };
};

template<class F>
struct function_traits<F&> : public function_traits<F>
{};

template<class F>
struct function_traits<F&&> : public function_traits<F>
{};

Testcode:

#include <iostream>

class A
{
};

template <class T>
struct Functor
{
  void operator()(const T& t)
  {}
};

struct Register
{
  //int parameters
  template <class T>
  static void RegisterFunctor(const T& /*functor*/, typename std::enable_if<std::is_same<typename function_traits<T>::template argument<0>::type, const int&>::value>::type* = 0)
  {
    std::cout << "Register int func" << std::endl;
  }

  //A parameters
  template <class T>
  static void RegisterFunctor(const T& /*functor*/, typename std::enable_if<std::is_same<typename function_traits<T>::template argument<0>::type, const A&>::value>::type* = 0)
  {
    std::cout << "Register int func" << std::endl;
  }
};

void intFunc(const int&) {}
void aFunc(const A&){}

int main(int /*argc*/, char */*argv*/[])
{
  Functor<int> intFunctor;
  Functor<A> aFunctor;

  Register::RegisterFunctor(intFunctor);
  Register::RegisterFunctor(&intFunc);
  Register::RegisterFunctor(aFunctor);
  Register::RegisterFunctor(&aFunc);
  return 0;
}

Answer 3

if F is a std::functionyou should be able to use the its member type and check with `std::is_same':

template<class F>
void register_handler( F& f ) // any callable object
{
   // find out T - the argument type of f
   if(std::is_same<int, F::argument_type>::value)
   { .... }
   //etc .....

}

An up and running example here

but that kind of code can quickly become a mess to maintain.

Answer 4

You could use sfinae and test if your argument is convertible to a std::function with the required arguments:

#include <type_traits>
#include <functional>
#include <iostream>

class A
{
};

template <class T>
struct Functor
{
  void operator()(const T& t)
  {}
};

struct Register
{
  //int parameters
  template <class T>
  static void RegisterFunctor(const T& /*functor*/, typename std::enable_if<std::is_constructible<typename std::function<void (int)>, T>::value >::type* = 0)
  {
    std::cout << "Register int func" << std::endl;
  }

  //A parameters
  template <class T>
  static void RegisterFunctor(const T& /*functor*/, typename std::enable_if<std::is_constructible<typename std::function<void (A)>, T>::value >::type* = 0)
  {
    std::cout << "Register a func" << std::endl;
  }
};

void intFunc(int) {}
void aFunc(A){}

int main(int /*argc*/, char */*argv*/[])
{
  Functor<int> intFunctor;
  Functor<A> aFunctor;

  Register::RegisterFunctor(intFunctor);
  Register::RegisterFunctor(&intFunc);
  Register::RegisterFunctor(aFunctor);
  Register::RegisterFunctor(&aFunc);
  return 0;
}