Is there a Python library to list primes?

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失恋的感觉
失恋的感觉 2020-12-09 04:28

Is there a library function that can enumerate the prime numbers (in sequence) in Python?

I found this question Fastest way to list all primes below N but I\'d rathe

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  • 2020-12-09 04:45

    The gmpy2 library has a next_prime() function. This simple function will create a generator that will provide an infinite supply of primes:

    import gmpy2
    
    def primes():
        n = 2
        while True:
            yield n
            n = gmpy2.next_prime(n)
    

    If you will be searching through primes repeatedly, creating and reusing a table of all primes below a reasonable limit (say 1,000,000) will be faster. Here is another example using gmpy2 and the Sieve of Eratosthenes to create a table of primes. primes2() returns primes from the table first and then uses next_prime().

    import gmpy2
    
    def primes2(table=None):
    
        def sieve(limit):
            sieve_limit = gmpy2.isqrt(limit) + 1
            limit += 1
            bitmap = gmpy2.xmpz(3)
            bitmap[4 : limit : 2] = -1
            for p in bitmap.iter_clear(3, sieve_limit):
                bitmap[p*p : limit : p+p] = -1
            return bitmap
    
        table_limit=1000000
        if table is None:
            table = sieve(table_limit)
    
        for n in table.iter_clear(2, table_limit):
            yield n
    
        n = table_limit
        while True:
            n = gmpy2.next_prime(n)
            yield n
    

    You can adjust table_limit to suit your needs. Larger values will require more memory and increase the startup time for the first invocation of primes() but it will be faster for repeated calls.

    Note: I am the maintainer of gmpy2.

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  • 2020-12-09 04:46

    SymPy is another choice. It is a Python library for symbolic mathematics. It provides several functions for prime.

    isprime(n)              # Test if n is a prime number (True) or not (False).
    
    primerange(a, b)        # Generate a list of all prime numbers in the range [a, b).
    randprime(a, b)         # Return a random prime number in the range [a, b).
    primepi(n)              # Return the number of prime numbers less than or equal to n.
    
    prime(nth)              # Return the nth prime, with the primes indexed as prime(1) = 2. The nth prime is approximately n*log(n) and can never be larger than 2**n.
    prevprime(n, ith=1)     # Return the largest prime smaller than n
    nextprime(n)            # Return the ith prime greater than n
    
    sieve.primerange(a, b)  # Generate all prime numbers in the range [a, b), implemented as a dynamically growing sieve of Eratosthenes. 
    

    Here are some examples.

    >>> import sympy
    >>> 
    >>> sympy.isprime(5)
    True
    >>> list(sympy.primerange(0, 100))
    [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
    >>> sympy.randprime(0, 100)
    83
    >>> sympy.randprime(0, 100)
    41
    >>> sympy.prime(3)
    5
    >>> sympy.prevprime(50)
    47
    >>> sympy.nextprime(50)
    53
    >>> list(sympy.sieve.primerange(0, 100))
    [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
    
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  • 2020-12-09 04:47

    There is no constant time algorithm to generate the next prime number; this is why most libraries require an upper bound. This is actually a huge problem that needed to be solved for digital cryptography. RSA chooses sufficiently large primes by selecting a random number and testing for primality until it finds a prime.

    Given an arbitrary integer N, the only way to find the next prime after N is to iterate through N+1 to the unknown prime P testing for primality.

    Testing for primality is very cheap, and there are python libraries that do so: AKS Primes algorithm in Python

    Given a function test_prime, than an infinite primes iterator will look something like:

    class IterPrimes(object):
        def __init__(self,n=1):
            self.n=n
    
        def __iter__(self):
            return self
    
        def next(self):
            n = self.n
            while not test_prime(n):
                n += 1
            self.n = n+1
            return n
    

    There are a lot of heuristics you could use to speed up the process. For instance, skip even numbers, or numbers divisible by 2,3,5,7,11,13,etc..

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  • 2020-12-09 04:58

    Since asking this question, I wrote a Python wrapper around the C++ library primesieve. https://github.com/hickford/primesieve-python

    >>> from primesieve import *
    
    # Generate a list of the primes below 40
    >>> generate_primes(40)
    [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]
    
    # Generate a list of the primes between 100 and 120
    >>> generate_primes(100, 120)
    [101, 103, 107, 109, 113]
    
    # Generate a list of the first 10 primes
    >>> generate_n_primes(10)
    [2, 3, 5, 7, 11, 13, 17, 19, 23, 29]
    
    # Generate a list of the first 10 starting at 1000
    >>> generate_n_primes(10, 1000)
    [1009, 1013, 1019, 1021, 1031, 1033, 1039, 1049, 1051, 1061]
    
    # Get the 10th prime
    >>> nth_prime(10)
    29
    
    # Count the primes below 10**9
    >>> count_primes(10**9)
    50847534
    
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