Passing an optional parameter in PHP Function [duplicate]

Answer 1

1) You can define default values for arguments like so:

function test($required, $optional = false) {}

2) You can use func_num_args() to get the number of arguments, func_get_arg($n) to get the n'th argument or func_get_args() to get an array of all arguments.

You can find a good summary here: Function arguments

Answer 2

You can also do this:

function test($required, $optional = ''){
    #code
}

when calling:

test($required)

or:

test($required, $optional = 'something')

Answer 3

just set the default parameters in your function ex.

function test($required, $optional = null, ... )

now you can call your function like this

test($required, $optional)
test($required);

Answer 4

With a default value:

function test($required, $optional="default value"){..}

Answer 5

read this http://php.net/manual/en/function.func-get-args.php

dont pass any argument when decalare a function like below

function myMin() {
      $list = func_get_args();
      $min = NULL;
      if (count($list)>0) $min = $list[0];
      for ($i=1; $i<count($list); $i++) {
         if ($min > $list[$i]) $min = $list[$i];
      }
      return $min;
   }

   print("\n Calling a function that uses func_get_args():\n");
   print("    ".myMin()."\n");
   print("    ".myMin(5)."\n");
   print("    ".myMin(5, 6, 2)."\n");
   print("    ".myMin(5, 6, 2, 9, 5, 1, 4, 1, 3)."\n");
?>

Answer 6

try this:

function test($required, $optional = NULL){..} 

then you can call

test($required, $optional)

and with $optional null

test($required);