Get sidekiq to execute a job immediately

Question

At the moment, I have a sidekiq job like this:

class SyncUser
  include Sidekiq::Worker

  def perform(user_id)
    #do stuff
  end
end

I a

Answer 1

Use SyncUser.perform_now(user.id)

Answer 2

There are two questions here.

If you want to execute a job immediately, in the current context you can use:

SyncUser.new.perform(user.id)

If you want to decrease the delay between asynchronous work being scheduled and when it's executed in the sidekiq worker, you can decrease the poll_interval setting:

Sidekiq.configure_server do |config|
  config.poll_interval = 2
end

The poll_interval is the delay within worker backends of how frequently workers check for jobs on the queue. The average time between a job being scheduled and executed with a free worker will be poll_interval / 2.