Exit while loop by user hitting ENTER key

Question

I am a python newbie and have been asked to carry out some exercises using while and for loops. I have been asked to make a program loop until exit is requested by the user

Answer 1

The following works from me:

i = '0'
while len(i) != 0:
    i = list(map(int, input(),split()))

Answer 2

a very simple solution would be, and I see you have said that you would like to see the simplest solution possible. A prompt for the user to continue after halting a loop Etc.

raw_input("Press<enter> to continue")

Answer 3

If you want your user to press enter, then the raw_input() will return "", so compare the User with "":

User = raw_input('Press enter to exit...')
running = 1
while running == 1:
    Run your program
if User == "":
    break
else
    running == 1

Answer 4

The exact thing you want ;)

https://stackoverflow.com/a/22391379/3394391

import sys, select, os

i = 0
while True:
    os.system('cls' if os.name == 'nt' else 'clear')
    print "I'm doing stuff. Press Enter to stop me!"
    print i
    if sys.stdin in select.select([sys.stdin], [], [], 0)[0]:
        line = raw_input()
        break
    i += 1

Answer 5

This works for python 3.5 using parallel threading. You could easily adapt this to be sensitive to only a specific keystroke.

import time
import threading


# set global variable flag
flag = 1

def normal():
    global flag
    while flag==1:
        print('normal stuff')
        time.sleep(2)
        if flag==False:
            print('The while loop is now closing')

def get_input():
    global flag
    keystrk=input('Press a key \n')
    # thread doesn't continue until key is pressed
    print('You pressed: ', keystrk)
    flag=False
    print('flag is now:', flag)

n=threading.Thread(target=normal)
i=threading.Thread(target=get_input)
n.start()
i.start()

Answer 6

You need to find out what the variable User would look like when you just press Enter. I won't give you the full answer, but a tip: Fire an interpreter and try it out. It's not that hard ;) Notice that print's sep is '\n' by default (was that too much :o)