I\'ve seen some similar types of questions on SO, however, I have not been able to find a solution to my specific issue. (FYI, these are not my real columns, just a shorten
This is all i got.
SELECT timestamp
FROM my_table
WHERE user_22 = '22'
ORDER BY timestamp DESC /*or ASC*/
And when you query it the codewould be
while($row = mysql_fetch_array(the sql query)){
$timestamp = $row['timestamp']
}
If someone has a similar problem in SQL Server, this will work for you (the suggested MySQL query in the previous post doesn't work in SQL Server):
SELECT * FROM my_table
WHERE timestamp = ( SELECT MAX( timestamp ) FROM my_table
WHERE user_2 = 22 )
SELECT * FROM my_table -- standard stuff
WHERE user_2 = 22 -- predicate
ORDER BY timestamp DESC -- this means highest number (most recent) first
LIMIT 1; -- just want the first row
Edit:
By the way, in case you're curious why your original query didn't work, let's break down the pieces:
my_table
...user_2
= 22timestamp
= (some value, let's put it aside for now)Now, coming back to that timestamp
value, it comes from your subquery:
SELECT MAX( timestamp ) FROM my_table
Note that this subquery doesn't restrict any rows based on user_2
-- it asks for what's the max timestamp in the whole table. That max timestamp is the first one in your table above: (user_1 = 23, user_2 = 25, timestamp = 2012-08-10 22:00:00).
So, let's plug that back to the top-level query:
my_table
...... and you can see there isn't such a row.
Another method is to GROUP BY
the user_2
column as you calculate MAX(timestamp)
. Doing so will make MAX(timestamp)
calculate not the latest date in the entire table, but rather the latest timestamp for each group of records with the same user_2
value.
So, for example, your query could be:
SELECT * FROM my_table
WHERE user_2 = 22
AND timestamp =
(SELECT MAX(timestamp) FROM my_table
WHERE user_2 = 22
GROUP BY user_2)
LIMIT 1;
This query is adapted from the answer I found in this excellent answer.