How to return part of string before a certain character?

Question

If you look at the jsfiddle from question,

var str = \"Abc: Lorem ipsum sit amet\";
str = str.substring(str.indexOf(\":\") + 1);

This retur

Answer 1

And note that first argument of subString is 0 based while second is one based.

Example:

String str= "0123456";
String sbstr= str.substring(0,5);

Output will be sbstr= 01234 and not sbstr = 012345

Answer 2

You fiddle already does the job ... maybe you try to get the string before the double colon? (you really should edit your question) Then the code would go like this:

str.substring(0, str.indexOf(":"));

Where 'str' represents the variable with your string inside.

Click here for JSFiddle Example

Javascript

var input_string = document.getElementById('my-input').innerText;
var output_element = document.getElementById('my-output');

var left_text = input_string.substring(0, input_string.indexOf(":"));

output_element.innerText = left_text;

Html

<p>
  <h5>Input:</h5>
  <strong id="my-input">Left Text:Right Text</strong>
  <h5>Output:</h5>
  <strong id="my-output">XXX</strong>
</p>

CSS

body { font-family: Calibri, sans-serif; color:#555; }
h5 { margin-bottom: 0.8em; }
strong {
  width:90%;
  padding: 0.5em 1em;
  background-color: cyan;
}
#my-output { background-color: gold; }

Answer 3

Another method could be to split the string by ":" and then pop off the end. var newString = string.split(":").pop();

Answer 4

In General a function to return string after substring is

function getStringAfterSubstring(parentString, substring) {
    return parentString.substring(parentString.indexOf(substring) + substring.length)
}

function getStringBeforeSubstring(parentString, substring) {
    return parentString.substring(0, parentString.indexOf(substring))
}
console.log(getStringAfterSubstring('abcxyz123uvw', '123'))
console.log(getStringBeforeSubstring('abcxyz123uvw', '123'))