How do I specify an integer literal of type unsigned char in C++?

Question

I can specify an integer literal of type unsigned long as follows:

const unsigned long example = 9UL;

How do I do likewise for an unsigned

Answer 1

The question was how to "specify an integer 'literal' of type unsigned char in C++?". Not how to declare an identifier.

You use the escape backslash and octal digits in apostrophes. (eg. '\177')

The octal value is always taken to be unsigned.

Answer 2

I suppose '\0' would be a char literal with the value 0, but I don't see the point either.

Answer 3

Assuming that you are using std::min what you actually should do is explicitly specify what type min should be using as such

unsigned char example2 = 0;
min<unsigned char>(9, example2);