Convert char array to string use C

Question

I need to convert a char array to string. Something like this:

char array[20];
char string[100];

array[0]=\'1\';
array[1]=\'7\';
array[2]=\'8\';
array[3]=\'         


        

Answer 1

You're saying you have this:

char array[20]; char string[100];
array[0]='1'; 
array[1]='7'; 
array[2]='8'; 
array[3]='.'; 
array[4]='9';

And you'd like to have this:

string[0]= "178.9"; // where it was stored 178.9 ....in position [0]

You can't have that. A char holds 1 character. That's it. A "string" in C is an array of characters followed by a sentinel character (NULL terminator).

Now if you want to copy the first x characters out of array to string you can do that with memcpy():

memcpy(string, array, x);
string[x] = '\0'; 

Answer 2

You can use strcpy but remember to end the array with '\0'

char array[20]; char string[100];

array[0]='1'; array[1]='7'; array[2]='8'; array[3]='.'; array[4]='9'; array[5]='\0';
strcpy(string, array);
printf("%s\n", string);

Answer 3

Assuming array is a character array that does not end in \0, you will want to use strncpy:

char * strncpy(char * destination, const char * source, size_t num);

like so:

strncpy(string, array, 20);
string[20] = '\0'

Then string will be a null terminated C string, as desired.