php explode: split string into words by using space a delimiter

Question

$str = \"This is a    string\";
$words = explode(\" \", $str);

Works fine, but spaces still go into array:

$words === array (\'This         


        

Answer 1

Another way to do it would be using foreach loop.

$str = "This is a    string";
$words = explode(" ", $str);
$spaces=array();
$others=array();
foreach($words as $word)
{
if($word==' ')
{
array_push($spaces,$word);
}
else
{
array_push($others,$word);
}
}

Answer 2

Here are the results of performance tests:

$str = "This is a    string";

var_dump(time());

for ($i=1;$i<100000;$i++){
//Alma Do Mundo  - the winner
$rgData = preg_split('/\s+/', $str);


preg_match_all('/\s+/', $str, $rgMatches);
$rgResult = array_map('strlen', $rgMatches[0]);// [1,1,4]


}
print_r($rgData); print_r( $rgResult);
var_dump(time());




for ($i=1;$i<100000;$i++){
//nickb
$temp = preg_split('/(\s+)/', $str, -1,PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
$spaces = array();
$words = array_reduce( $temp, function( &$result, $item) use ( &$spaces) {
    if( strlen( trim( $item)) === 0) {
        $spaces[] = strlen( $item);
    } else {
        $result[] = $item;
    }
    return $result;
}, array());
}


print_r( $words); print_r( $spaces);
var_dump(time());

int(1378392870) Array ( [0] => This [1] => is [2] => a [3] => string ) Array ( [0] => 1 [1] => 1 [2] => 4 ) int(1378392871) Array ( [0] => This [1] => is [2] => a [3] => string ) Array ( [0] => 1 [1] => 1 [2] => 4 ) int(1378392873)

Answer 3

For splitting the String into an array, you should use preg_split:

$string = 'This is a    string';
$data   = preg_split('/\s+/', $string);

Your second part (counting spaces):

$string = 'This is a    string';
preg_match_all('/\s+/', $string, $matches);
$result = array_map('strlen', $matches[0]);// [1, 1, 4]

Answer 4

You can use preg_split() for the first array:

$str   = 'This is a    string';
$words = preg_split('#\s+#', $str);

And preg_match_all() for the $spaces array:

preg_match_all('#\s+#', $str, $m);
$spaces = array_map('strlen', $m[0]);

Answer 5

$financialYear = 2015-2016;

$test = explode('-',$financialYear);
echo $test[0]; // 2015
echo $test[1]; // 2016

Answer 6

Here is one way, splitting the string and running a regex once, then parsing the results to see which segments were captured as the split (and therefore only whitespace), or which ones are words:

$temp = preg_split('/(\s+)/', $str, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);

$spaces = array();
$words = array_reduce( $temp, function( &$result, $item) use ( &$spaces) {
    if( strlen( trim( $item)) === 0) {
        $spaces[] = strlen( $item);
    } else {
        $result[] = $item;
    }
    return $result;
}, array());

You can see from this demo that $words is:

Array
(
    [0] => This
    [1] => is
    [2] => a
    [3] => string
)

And $spaces is:

Array
(
    [0] => 1
    [1] => 1
    [2] => 4
)