How to match a substring in a string, ignoring case

Question

I\'m looking for ignore case string comparison in Python.

I tried with:

if line.find(\'mandy\') >= 0:

but no success for ignore

Answer 1

a = "MandY"
alow = a.lower()
if "mandy" in alow:
    print "true"

work around

Answer 2

you can also use: s.lower() in str.lower()

Answer 3

If you don't want to use str.lower(), you can use a regular expression:

import re

if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
    # Is True

Answer 4

See this.

In [14]: re.match("mandy", "MaNdY", re.IGNORECASE)
Out[14]: <_sre.SRE_Match object at 0x23a08b8>

Answer 5

You can use in operator in conjunction with lower method of strings.

if "mandy" in line.lower():

Answer 6

Try:

if haystackstr.lower().find(needlestr.lower()) != -1:
  # True