Does C++ have any equivalent to python\'s function os.path.join
? Basically, I\'m looking for something that combines two (or more) parts of a file path so that
In Qt, just use /
in code when using Qt API (QFile
, QFileInfo
). It will do the right thing on all platforms. If you have to pass a path to a non-Qt function, or want to format it for displaying it to the user, use QDir:toNativeSeparators()
e.g.:
QDir::toNativeSeparators( path );
It will replace /
by the native equivalent (i.e. \
on Windows). The other direction is done via QDir::fromNativeSeparators()
.
Similar to @user405725's answer (but not using boost), and mentioned by @ildjarn in a comment, this functionality is available as part of std::filesystem. The following code compiles using Homebrew GCC 9.2.0_1 and using the flag --std=c++17
:
#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;
int main()
{
fs::path dir ("/tmp");
fs::path file ("foo.txt");
fs::path full_path = dir / file;
std::cout << full_path << std::endl;
return 0;
}
If you want to do this with Qt, you can use QFileInfo
constructor:
QFileInfo fi( QDir("/tmp"), "file" );
QString path = fi.absoluteFilePath();
Check out QDir for that:
QString path = QDir(dirPath).filePath(fileName);
Only as part of Boost.Filesystem library. Here is an example:
#include <iostream>
#include <boost/filesystem.hpp>
namespace fs = boost::filesystem;
int main ()
{
fs::path dir ("/tmp");
fs::path file ("foo.txt");
fs::path full_path = dir / file;
std::cout << full_path << std::endl;
return 0;
}
Here is an example of compiling and running (platform specific):
$ g++ ./test.cpp -o test -lboost_filesystem -lboost_system
$ ./test
/tmp/foo.txt
At least in Unix / Linux, it's always safe to join parts of a path by /
, even if some parts of the path already end in /
, i.e. root/path
is equivalent to root//path
.
In this case, all you really need is to join things on /
. That said, I agree with other answers that boost::filesystem
is a good choice if it is available to you because it supports multiple platforms.