ARMA out-of-sample prediction with statsmodels

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渐次进展 2020-12-08 11:51

I\'m using statsmodels to fit a ARMA model.

import statsmodels.api as sm
arma    = sm.tsa.ARMA(data, order =(4,4));
results = arma.fit( full_output=False, d         


        
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  • 2020-12-08 12:07

    I thought there was an issue for this. If you file one on github, I'll be more likely to remember to add something like this. The prediction machinery is not (yet) available as user-facing functions, so you'd have to do something like this.

    If you've fit a model already, then you can do this.

    # this is the nsteps ahead predictor function
    from statsmodels.tsa.arima_model import _arma_predict_out_of_sample
    res = sm.tsa.ARMA(y, (3, 2)).fit(trend="nc")
    
    # get what you need for predicting one-step ahead
    params = res.params
    residuals = res.resid
    p = res.k_ar
    q = res.k_ma
    k_exog = res.k_exog
    k_trend = res.k_trend
    steps = 1
    
    _arma_predict_out_of_sample(params, steps, residuals, p, q, k_trend, k_exog, endog=y, exog=None, start=len(y))
    

    This is a new prediction 1 step ahead. You can tack this on to y, and you'll need to update your residuals.

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  • 2020-12-08 12:20

    For univariate out-of sample prediction (test) We can use:

    ARMAResults.forecast(steps=1, exog=None, alpha=0.05)

    It would be res.forcast(steps=1)

    Same is available for ARIMA as well.

    ARIMAResults.forecast(steps=1, exog=None, alpha=0.05)

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