What is best way to get last indexof character in SQL 2008 [duplicate]

Answer 1

DECLARE @x VARCHAR(32) = 'xyzxyzyyythgetdghydgsh';
SELECT LEN(@x) - CHARINDEX('y', REVERSE(@x)) + 1;

Answer 2

A little tricky, but you could do something like:

REVERSE(SUBSTRING(REVERSE([field]),0,CHARINDEX('[char]',REVERSE([field]))))

Answer 3

Try this one out, analyze result step by step.

declare @string varchar(max)
declare @subString varchar(max)
set @string = 'this is a duplicated question,      but may get some new answers, since tech chagne from time to time as we know';
set @subString = 'this is a duplicated question,      but may get some new answers, since tech chagne from time to time'
--Find the string.lastIndexof(time)
select LEN(@String)
select LEN(@SubString)
select CHARINDEX('time', REVERSE(@string))
select reverse(@string)
select reverse('time')
SELECT LEN(@string) - CHARINDEX(reverse('time'), REVERSE(@string)) - Len('time') + 1