How to check if a character is upper-case in Python?

Question

I have a string like this

>>> x=\"Alpha_beta_Gamma\"
>>> words = [y for y in x.split(\'_\')]
>>> words
[\'Alpha\', \'beta\', \'Gam         


        

Answer 1

words = x.split("_")
for word in words:
    if word[0] == word[0].upper() and word[1:] == word[1:].lower():
        print word, "is conformant"
    else:
        print word, "is non conformant"

Answer 2

Use list(str) to break into chars then import string and use string.ascii_uppercase to compare against.

Check the string module: http://docs.python.org/library/string.html

Answer 3

Maybe you want str.istitle

>>> help(str.istitle)
Help on method_descriptor:

istitle(...)
    S.istitle() -> bool

    Return True if S is a titlecased string and there is at least one
    character in S, i.e. uppercase characters may only follow uncased
    characters and lowercase characters only cased ones. Return False
    otherwise.

>>> "Alpha_beta_Gamma".istitle()
False
>>> "Alpha_Beta_Gamma".istitle()
True
>>> "Alpha_Beta_GAmma".istitle()
False

Answer 4

You can use this code:

def is_valid(string):
    words = string.split('_')
    for word in words:
        if not word.istitle():
            return False, word
    return True, words
x="Alpha_beta_Gamma"
assert is_valid(x)==(False,'beta')
x="Alpha_Beta_Gamma"
assert is_valid(x)==(True,['Alpha', 'Beta', 'Gamma'])

This way you know if is valid and what word is wrong

Answer 5

You can use this regex:

^[A-Z][a-z]*(?:_[A-Z][a-z]*)*$

Sample code:

import re

strings = ["Alpha_beta_Gamma", "Alpha_Beta_Gamma"]
pattern = r'^[A-Z][a-z]*(?:_[A-Z][a-z]*)*$'

for s in strings:
    if re.match(pattern, s):
        print s + " conforms"
    else:
        print s + " doesn't conform"

As seen on codepad

Answer 6

x="Alpha_beta_Gamma"
is_uppercase_letter = True in map(lambda l: l.isupper(), x)
print is_uppercase_letter
>>>>True

So you can write it in 1 string