I am not very experience with java and this is driving me crazy. I wrote a java program FileManagement and I need to run it from the command line.
I can
Guys let's understand the syntax of it.
If class file is present in the Current Dir.
java -cp . fileName
If class file is present within the Dir. Go to the Parent Dir and enter below cmd.
java -cp . dir1.dir2.dir3.fileName
If there is a dependency on external jars then,
java -cp .:./jarName1:./jarName2 fileName
Hope this helps.
(This is the KISS answer.)
Let's say you have several .java files in the current directory:
$ ls -1 *.java
javaFileName1.java
javaFileName2.java
Let's say each of them have a main() method (so they are programs, not libs), then to compile them do:
javac *.java -d .
This will generate as many subfolders as "packages" the .java files are associated to. In my case all java files where inside under the same package name packageName, so only one folder was generated with that name, so to execute each of them:
java -cp . packageName.javaFileName1
java -cp . packageName.javaFileName2
What is the package name of your class? If there is no package name, then most likely the solution is:
java -cp FileManagement Main
If your Main class is in a package called FileManagement, then try:
java -cp . FileManagement.Main
in the parent folder of the FileManagement folder.
If your Main class is not in a package (the default package) then cd to the FileManagement folder and try:
java -cp . Main
More info about the CLASSPATH and how the JRE find classes: