Select and display only duplicate records in mysql

Question

This question is pretty simple I for some reason cant get the proper result to display only the duplicate records

Table   : Paypal_ipn_orders
id                      


        

Answer 1

SELECT * FROM `table` t1 join `table` t2 WHERE (t1.name=t2.name) && (t1.id!=t2.id)

Answer 2

SELECT id, payer_email FROM paypal_ipn_orders
WHERE payer_email IN (
    SELECT payer_email FROM papypal_ipn_orders GROUP BY payer_email HAVING COUNT(*) > 1)

Answer 3

use this code

 SELECT *  
    FROM  paypal_ipn_orders 
    GROUP BY  payer_email  
    HAVING COUNT( payer_email) >1  

Answer 4

Similar to this answer, though I used a temporary table instead:

CREATE TEMPORARY TABLE duplicates (
    SELECT payer_email
    FROM paypal_ipn_orders
    GROUP BY payer_email
    HAVING COUNT(id) > 1
);
SELECT id, payer_email
FROM paypal_ipn_orders AS p
INNER JOIN duplicates AS d ON d.payer_email=p.payer_email;

Answer 5

This works the fastest for me

SELECT
    primary_key
FROM
    table_name
WHERE
    primary_key NOT IN (
        SELECT
            primary_key
        FROM
            table_name
        GROUP BY
            column_name
        HAVING
            COUNT(*) = 1
    );

Answer 6

Hi above answer will not work if I want to select one or more column value which is not same or may be same for both row data

For Ex. I want to select username, birth date also. But in database is username is not duplicate but birth date will be duplicate then this solution will not work.

For this use this solution Need to take self join on same table/

SELECT  
    distinct(p1.id),  p1.payer_email , p1.username, p1.birth_date

FROM 
    paypal_ipn_orders AS p1 

INNER JOIN paypal_ipn_orders AS p2 

ON p1.payer_email=p2.payer_email

WHERE 

p1.birth_date=p2.birth_date

Above query will return all records having same email_id and same birth date