regular expression for DOT [duplicate]

Answer 1

Use String.Replace() if you just want to replace the dots from string. Alternative would be to use Pattern-Matcher with StringBuilder, this gives you more flexibility as you can find groups that are between dots. If using the latter, i would recommend that you ignore empty entries with "\\.+".

public static int count(String str, String regex) {
    int i = 0;
    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(str);
    while (m.find()) {
        m.group();
        i++;
    }
    return i;
}

public static void main(String[] args) {
    int i = 0, j = 0, k = 0;
    String str = "-.-..-...-.-.--..-k....k...k..k.k-.-";

    // this will just remove dots
    System.out.println(str.replaceAll("\\.", ""));
    // this will just remove sequences of ".." dots
    System.out.println(str.replaceAll("\\.{2}", ""));
    // this will just remove sequences of dots, and gets
    // multiple of dots as 1
    System.out.println(str.replaceAll("\\.+", ""));

    /* for this to be more obvious, consider following */
    System.out.println(count(str, "\\."));
    System.out.println(count(str, "\\.{2}"));
    System.out.println(count(str, "\\.+"));
}

The output will be:

--------kkkkk--
-.--.-.-.---kk.kk.k-.-
--------kkkkk--
21
7
11

Answer 2

...

[.]{1}

or

[.]{2}

?

Answer 3

[+*?.] Most special characters have no meaning inside the square brackets. This expression matches any of +, *, ? or the dot.

Answer 4

. matches any character so needs escaping i.e. \., or \\. within a Java string (because \ itself has special meaning within Java strings.)

You can then use \.\. or \.{2} to match exactly 2 dots.

Answer 5

You should use contains not matches

if(nom.contains("."))
    System.out.println("OK");
else
    System.out.println("Bad");