Select all where [first letter starts with B]

Question

This is a follow up question to my previous one. I want to write a MYSQL statement that echoes every entry that starts with letter B.

Function.php

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Answer 1

Following your comment posted to ceejayoz's answer, two things are messed up a litte:

1. $first is not an array, it's a string. Replace $first = $first[0] . "%" by $first .= "%". Just for simplicity. (PHP string operators)

2. The string being compared with LIKE operator should be quoted. Replace LIKE ".$first."") by LIKE '".$first."'"). (MySQL String Comparison Functions)

Answer 2

You can use:

WHERE LEFT (name_field, 1) = 'B';

Answer 3

This will work for MYSQL

SELECT Name FROM Employees WHERE Name REGEXP '^[B].*$'

In this REGEXP stands for regular expression

and

this is for T-SQL

SELECT Name FROM Employees WHERE Name LIKE '[B]%'

Answer 4

SELECT author FROM lyrics WHERE author LIKE 'B%';

Make sure you have an index on author, though!

Answer 5

SQL Statement:

 SELECT * FROM employee WHERE employeeName LIKE 'A%';

Result:

Number of Records: 4

employeeID  employeeName    employeeName    Address City    PostalCode  Country

1           Alam             Wipro          Delhi   Delhi   11005      India

2           Aditya           Wipro          Delhi   Delhi   11005      India

3           Alok             HCL            Delhi   Delhi   11005      India

4           Ashok            IBM            Delhi   Delhi   11005      India