Batch file stops running after the first command

Question

I am using the tool \'HTML Match\' to compare two HTML files. As I have to compare many files, I create a batch file like the followion. For example, I give only five sets o

Answer 1

You don't have to insert quotation marks where there isn't any space mark between.

Try that:

HTMLMATCH.EXE D:\Raj\compare1\a1.html D:\Raj\compare2\a1.html D:\Raj\compare_res\a1.html

Maybe it will solve your issue.

Answer 2

The answer to your problem is to write CALL HTMLMATCH.EXE (and the rest of the parameters). Just use CALL in front of every executable command in the batch file.

Answer 3

Add call in front of the commands you're running.

You can also change this to a for loop, so:

FOR /L %%i in (1,1,5) DO CALL HTMLMATCH.EXE D:\Raj\compare%%i%%\a%%i%%.html D:\Raj\compare%%i%%\a%%i%%.html D:\Raj\compare_res\a%%i%%.html

Answer 4

I was looking for something really similar and tried, I think, all the replies left here but I finally found the solution to my problem!!

In my script I want to check if one process is running, if not, start it (a .exe) and then check if another process is running, if not, start it too (but leave all the programs opened) and the problem is that the first .exe was started but then not moving to the second one because it was waiting until the process ended. It´s finally working for me with start and the magic comes with...

/separate

it works for me as:

start "program1" /separate program1.exe
other commands

Before it stopped after starting program1 because it was waiting until it was closed, I think, but this was not going to happen because I wanted to leave it opened. Now with the start /separate it continues with the other commands.

I found it in another forum but the thing is that it´s the manual, /separate is used to start in another memory space.