enumerate() for dictionary in python

Question

I know we use enumerate for iterating a list but I tried it in a dictionary and it didn\'t give an error.

CODE:

enumm = {0: 1, 1: 2, 2:          


        

Answer 1

d = {0: 'zero', '0': 'ZERO', 1: 'one', '1': 'ONE'}

print("List of enumerated d= ", list(enumerate(d.items())))

output:

List of enumerated d=  [(0, (0, 'zero')), (1, ('0', 'ZERO')), (2, (1, 'one')), (3, ('1', 'ONE'))]

Answer 2

Just thought I'd add, if you'd like to enumerate over the index, key, and values of a dictionary, your for loop should look like this:

for index, (key, value) in enumerate(your_dict.items()):
    print(index, key, value)

Answer 3

You may find it useful to include index inside key:

d = {'a': 1, 'b': 2}
d = {(i, k): v for i, (k, v) in enumerate(d.items())}

Output:

{(0, 'a'): True, (1, 'b'): False}

Answer 4

dict1={'a':1, 'b':'banana'}

To list the dictionary in Python 2.x:

for k,v in dict1.iteritems():
        print k,v 

In Python 3.x use:

for k,v in dict1.items():
        print(k,v)
# a 1
# b banana

Finally, as others have indicated, if you want a running index, you can have that too:

for i  in enumerate(dict1.items()):
   print(i)  

 # (0, ('a', 1))
 # (1, ('b', 'banana'))

But this defeats the purpose of a dictionary (map, associative array) , which is an efficient data structure for telephone-book-style look-up. Dictionary ordering could be incidental to the implementation and should not be relied upon. If you need the order, use OrderedDict instead.

Answer 5

That sure must seem confusing. So this is what is going on. The first value of enumerate (in this case i) returns the next index value starting at 0 so 0, 1, 2, 3, ... It will always return these numbers regardless of what is in the dictionary. The second value of enumerate (in this case j) is returning the values in your dictionary/enumm (we call it a dictionary in Python). What you really want to do is what roadrunner66 responded with.