Scala - ScheduledFuture

Question

I am trying to implement scheduled future in Scala. I would like it to wait specific time and then execute the body. So far I tried the following, simple approach

Answer 1

If you want schedule the completion without Akka, you can use a regular Java Timer to schedule a promise to complete:

def delay[T](delay: Long)(block: => T): Future[T] = {
  val promise = Promise[T]()
  val t = new Timer()
  t.schedule(new TimerTask {
    override def run(): Unit = {
      promise.complete(Try(block))
    }
  }, delay)
  promise.future
}

Answer 2

You could change your code to something like this:

val d = 5.seconds.fromNow
val f = Future {delay(d); 1}
val res = Await.result(f, Duration.Inf)

def delay(dur:Deadline) = {
  Try(Await.ready(Promise().future, dur.timeLeft))
}

But I would not recommend it. In doing so, you would be blocking in a Future (blocking to wait for that Promise that will never complete), and I think blocking in the ExecutionContext is greatly discouraged. I would either look into using the java scheduled executor as you stated or you could look into using Akka as @alex23 recommended.

Answer 3

My solution is pretty similar to Régis's but I use Akka to schedule:

 def delayedFuture[T](delay: FiniteDuration)(block: => T)(implicit executor : ExecutionContext): Future[T] = {
    val promise = Promise[T]

    Akka.system.scheduler.scheduleOnce(delay) {
      try {
        val result = block
        promise.complete(Success(result))
      } catch {
        case t: Throwable => promise.failure(t)
      }
    }
    promise.future
  }

Answer 4

Shortest solution for this, is probably making use of scala-async:

import scala.async.Async.{async, await}

def delay[T](value: T, t: duration): Future[T] = async {
  Thread.sleep(t.toMillis)
  value
}

Or in case you want delayed execution of a block

def delay[T](t: duration)(block: => T): Future[T] async {
  Thread.sleep(t.toMillis)
  block()
}

Answer 5

Akka has akka.pattern:

def after[T](duration: FiniteDuration, using: Scheduler)(value: ⇒ Future[T])(implicit ec: ExecutionContext): Future[T]

"Returns a scala.concurrent.Future that will be completed with the success or failure of the provided value after the specified duration."

http://doc.akka.io/api/akka/2.2.1/#akka.pattern.package

Answer 6

There is nothing to do that out of the box using the standard library alone. For most simple use cases, you can use a little helper such as this:

object DelayedFuture {
  import java.util.{Timer, TimerTask}
  import java.util.Date
  import scala.concurrent._
  import scala.concurrent.duration.FiniteDuration
  import scala.util.Try

  private val timer = new Timer(true)

  private def makeTask[T]( body: => T )( schedule: TimerTask => Unit )(implicit ctx: ExecutionContext): Future[T] = {
    val prom = Promise[T]()
    schedule(
      new TimerTask{
        def run() {
          // IMPORTANT: The timer task just starts the execution on the passed
          // ExecutionContext and is thus almost instantaneous (making it 
          // practical to use a single  Timer - hence a single background thread).
          ctx.execute( 
            new Runnable {
              def run() {
                prom.complete(Try(body))
              }
            }
          )
        }
      }
    )
    prom.future
  }
  def apply[T]( delay: Long )( body: => T )(implicit ctx: ExecutionContext): Future[T] = {
    makeTask( body )( timer.schedule( _, delay ) )
  }
  def apply[T]( date: Date )( body: => T )(implicit ctx: ExecutionContext): Future[T] = {
    makeTask( body )( timer.schedule( _, date ) )
  }
  def apply[T]( delay: FiniteDuration )( body: => T )(implicit ctx: ExecutionContext): Future[T] = {
    makeTask( body )( timer.schedule( _, delay.toMillis ) )
  }
}

This can be used like this:

import scala.concurrent.duration._
import scala.concurrent.ExecutionContext.Implicits._

DelayedFuture( 5 seconds )( println("Hello") )

Note that unlike java scheduled futures, this implementation will not let you cancel the future.