Request string without GET arguments [duplicate]

Answer 1

Not everyone will find it simple, but I believe this to be the best way to go around it:

preg_match('/^[^\?]+/', $_SERVER['REQUEST_URI'], $return);
$url = 'http' . ('on' === $_SERVER['HTTPS'] ? 's' : '') . '://' . $_SERVER['HTTP_HOST'] . $return[0]

What is does is simply to go through the REQUEST_URI from the beginning of the string, then stop when it hits a "?" (which really, only should happen when you get to parameters).

Then you create the url and save it to $url:
When creating the $url... What we're doing is simply writing "http" then checking if https is being used, if it is, we also write "s", then we concatenate "://", concatenate the HTTP_HOST (the server, fx: "stackoverflow.com"), and concatenate the $return, which we found before, to that (it's an array, but we only want the first index in it... There can only ever be one index, since we're checking from the beginning of the string in the regex.).

I hope someone can use this...

PS. This has been confirmed to work while using SLIM to reroute the URL.

Answer 2

Solution:

echoparse_url($_SERVER["REQUEST_URI"], PHP_URL_PATH);

Answer 3

Here is a solution that takes into account different ports and https:

$pageURL = (@$_SERVER['HTTPS'] == 'on') ? 'https://' : 'http://';

if ($_SERVER['SERVER_PORT'] != '80')
  $pageURL .= $_SERVER['SERVER_NAME'].':'.$_SERVER['SERVER_PORT'].$_SERVER['PHP_SELF'];
else 
  $pageURL .= $_SERVER['SERVER_NAME'].$_SERVER['PHP_SELF'];  

Or a more basic solution that does not take other ports into account:

$pageURL = (@$_SERVER['HTTPS'] == 'on') ? 'https://' : 'http://';
$pageURL .= $_SERVER['SERVER_NAME'].$_SERVER['PHP_SELF']; 

Answer 4

You can use $_SERVER['REQUEST_URI'] to get requested path. Then, you'll need to remove the parameters...

$uri_parts = explode('?', $_SERVER['REQUEST_URI'], 2);

Then, add in the hostname and protocol.

echo 'http://' . $_SERVER['HTTP_HOST'] . $uri_parts[0];

You'll have to detect protocol as well, if you mix http: and https://. That I leave as an exercise for you. $_SERVER['REQUEST_SCHEME'] returns the protocol.

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Putting it all together:

echo $_SERVER['REQUEST_SCHEME'] .'://'. $_SERVER['HTTP_HOST'] 
     . explode('?', $_SERVER['REQUEST_URI'], 2)[0];

...returns, for example:

http://example.com/directory/file.php

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php.com Documentation:

• $_SERVER — Server and execution environment information
• explode — Split a string by a string
• parse_url — Parse a URL and return its components (possibly a better solution)

Answer 5

I actually think that's not the good way to parse it. It's not clean or it's a bit out of subject ...

• Explode is heavy
• Session is heavy
• PHP_SELF doesn't handle URLRewriting

I'd do something like ...

if ($pos_get = strpos($app_uri, '?')) $app_uri = substr($app_uri, 0, $pos_get);

• This detects whether there's an actual '?' (GET standard format)
• If it's ok, that cuts our variable before the '?' which's reserved for getting datas

Considering $app_uri as the URI/URL of my website.

Answer 6

Why so complicated? =)

$baseurl = 'http://mysite.com';
$url_without_get = $baseurl.$_SERVER['PHP_SELF'];

this should really do it man ;)