Javascript getElement by href?

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长情又很酷
长情又很酷 2020-12-08 02:26

I\'ve got the script below

var els = document.getElementsByTagName(\"a\");
for(var i = 0, l = els.length; i < l; i++) {
  var el = els[i];
  el.innerHTML          


        
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  • 2020-12-08 02:42

    Reading and writing the innerHTML property on every element is probably quite expensive and hence causing your slowdown - it forces the browser to "serialize" the element, which you then run through a regexp, and then "deserialize" again. Even worse, you're doing it for every a element, even if it doesn't match.

    Instead, try looking directly at the properties of the a element:

    var els = document.getElementsByTagName("a");
    for (var i = 0, l = els.length; i < l; i++) {
        var el = els[i];
        if (el.href === 'http://www.example.com/') {
            el.innerHTML = "dead link";
            el.href = "#";
        }
    }
    

    EDIT on modern browsers with much greater W3C conformance you can now use document.querySelectorAll() to more efficiently obtain just the links you want:

    var els = document.querySelectorAll('a[href^=http://www.example.com/]');
    for (var i = 0, l = els.length; i < l; i++) {
        els[i].textContent = 'dead link';
        els[i].href = '#';
    }
    

    This is however not so flexible if there are multiple domain names that you wish to match, or for example if you want to match both http: and https: at the same time.

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  • 2020-12-08 02:45

    2016 update

    It's been over 4 years since this question was posted and things progressed quite a bit.

    You can't use:

    var els = document.getElementsByTagName("a[href='http://domain.com']");
    

    but what you can use is:

    var els = document.querySelectorAll("a[href='http://domain.com']");
    

    (Note: see below for browser support)

    which would make the code from your question work exactly as you expect:

    for (var i = 0, l = els.length; i < l; i++) {
      var el = els[i];
      el.innerHTML = el.innerHTML.replace(/link1/gi, 'dead link');
    }
    

    You can even use selectors like a[href^='http://domain.com'] if you want all links that start with 'http://domain.com':

    var els = document.querySelectorAll("a[href^='http://domain.com']");
    
    for (var i = 0, l = els.length; i < l; i++) {
      var el = els[i];
      el.innerHTML = el.innerHTML.replace(/link/gi, 'dead link');
    }
    

    See: DEMO

    Browser support

    The browser support according to Can I use as of June 2016 looks pretty good:

    (See: http://caniuse.com/queryselector for up to date info)

    There is no support in IE6 and IE7 but IE6 is already dead and IE7 soon will be with its 0.68% market share.

    IE8 is over 7 years old and it partially supports querySelectorAll - by "partially" I mean that you can use CSS 2.1 selectors like [attr], [attr="val"], [attr~="val"], [attr|="bar"] and a small subset of CSS 3 selectors which luckily include: [attr^=val], [attr$=val], and [attr*=val] so it seems that IE8 is fine with my examples above.

    IE9, IE10 and IE11 all support querySelectorAll with no problems, as do Chrome, Firefox, Safari, Opera and all other major browser - both desktop and mobile.

    In other words, it seems that we can safely start to use querySelectorAll in production.

    More info

    For more info, see:

    • https://developer.mozilla.org/en-US/docs/Web/API/Document/querySelectorAll
    • https://developer.mozilla.org/en-US/docs/Web/API/Document/querySelector
    • http://caniuse.com/queryselector

    See also this answer for the difference between querySelectorAll, querySelector, queryAll and query and when they were removed from the DOM specification.

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