Select rows with same id but different value in another column

Question

I tried for hours and read many posts but I still can\'t figure out how to handle this request:

I have a table like this:

+------+------+
|ARIDNR|LIE         


        

Answer 1

You can simply achieve it by

SELECT *
FROM test
WHERE ARIDNR IN
    (SELECT ARIDNR FROM test
     GROUP BY ARIDNR
     HAVING COUNT(*) > 1)
GROUP BY ARIDNR, LIEFNR;

Thanks.

Answer 2

This ought to do it:

SELECT *
FROM YourTable
WHERE ARIDNR IN (
    SELECT ARIDNR
    FROM YourTable
    GROUP BY ARIDNR
    HAVING COUNT(*) > 1
)

The idea is to use the inner query to identify the records which have a ARIDNR value that occurs 1+ times in the data, then get all columns from the same table based on that set of values.

Answer 3

Select A.ARIDNR,A.LIEFNR
from Table A
join Table B
on A.ARIDNR = B.ARIDNR
and A.LIEFNR<> B.LIEFNR
group by A.ARIDNR,A.LIEFNR

Answer 4

This is an old question yet I find that I also need a solution for this from time to time. The previous answers are all good and works well, I just personally prefer using CTE, for example:

DECLARE @T TABLE (ARIDNR INT, LIEFNR varchar(5)) --table variable for loading sample data
INSERT INTO @T (ARIDNR, LIEFNR) VALUES (1,'A'),(2,'A'),(3,'A'),(1,'B'),(2,'B'); --add your sample data to it
WITH duplicates AS --the CTE portion to find the duplicates
(
    SELECT ARIDNR FROM @T GROUP BY ARIDNR HAVING COUNT(*) > 1
)
SELECT t.* FROM @T t --shows results from main table
INNER JOIN duplicates d on t.ARIDNR = d.ARIDNR --where the main table can be joined to the duplicates CTE

---

Yields the following results:

1|A
1|B
2|B
2|A

Answer 5

Use this

select * from (
 SELECT ARIDNR,LIEFNR,row_number() over 
     (partition by ARIDNR order by ARIDNR) as RowNum) a
where a.RowNum >1

Answer 6

Try this please. I checked it and it's working:

SELECT *
FROM Table
WHERE ARIDNR IN (
    SELECT ARIDNR
    FROM Table
    GROUP BY ARIDNR
    HAVING COUNT(distinct LIEFNR) > 1
)