Fixing a broken loop by changing exactly one character

Answer 1

    for( i = 0; i < n; n-- )  
    printf("-");  

Changed i-- to n--

Answer 2

Here is another one:

#include <stdio.h>

int main()
{
    int i;
    int n = -20; //make n negative
    for( i = 0; i < n; i-- ) 
        printf("-");
    return 0;
}

Answer 3

Third answer:

for( i = 0; i + n; i-- )  
    printf("-"); 

Thanks to Gab Royer for inspiration.

Explanation: Eventually , i + n will result in -20 + 20 = 0 which is false.

Answer 4

Here's one of them, I think:

for( i = 0; i < n; n-- )

Answer 5

Here is one solution:

for( i = 0; -i < n; i-- )
        printf("-");

Here is a second one, thanks to Mark for helping me!

for( i = 0; i + n; i-- )
    printf("-");

And Mark also had the third one which is

for( i = 0; i < n; n-- )
    printf("-");

Answer 6

The comparison in the for loop can be any expression - you can negate i.

for (i = 0; -i < n ; i--)