I am using standard JPA transaction manager for my JPA transactions. However, now I want to add some JDBC entities which will share the same \'datasource\'. How can I make t
I've not really worked this out in detail yet as I've not mixed both JDBC and JPA but if you get your JDBC connection for an XA datasource then they are JTA transaction. So if you run your code in Stateless session bean for example with transaction turned on, then you automatically get both your Entities and JDBC managed by JTA.
EDIT
Here is an example code from Servlet
private @Resource DataSource xaDatasource;
private @Resource UserTransaction utx;
private @PersistenceUnit EntityManagerFactory factory;
public void doGet(HttpServletRequest req, HttpServletResponse res) ... {
utx.begin();
//Everything below this will be in JTA
Connection conn = xaDatasource.getConnection();
EntityManager mgr = factory.createEntityManager();
//Do your stuff
...
utx.commit();
}
Disclaimer: Code not tested.
Just realize this is not Spring but I'll leave it up anyway
It's possible to mix JPA and JDBC code in the same transaction using the JpaTransactionManager
.
A snippet from Spring 3's JavaDoc:
This transaction manager also supports direct DataSource access within a transaction (i.e. plain JDBC code working with the same DataSource). This allows for mixing services which access JPA and services which use plain JDBC (without being aware of JPA)!
You should be aware though that JPA caches the queries and executes all of them at the end of a transaction. So if you want to persist some data inside a transaction with JPA and then retrieve the data with JDBC, it will not work without explicitely flushing the JPA's persistence context before you attempt to retreive it with JDBC code.
A code example that asserts with JDBC code that the JPA code deleted a row inside a transaction:
@Test
@Transactional
@Rollback(false)
public void testDeleteCoffeeType() {
CoffeeType coffeeType = coffeeTypeDao.findCoffeeType(4L);
final String caffeForte = coffeeType.getName();
coffeeTypeDao.deleteCoffeeType(coffeeType);
entityManager.flush();
int rowsFoundWithCaffeForte = jdbcTemplate
.queryForInt("SELECT COUNT(*) FROM COFFEE_TYPES where NAME = ?",
caffeForte);
assertEquals(0, rowsFoundWithCaffeForte);
}
And if you prefer to use the JpaTemplate
class, just replace the entityManager.flush()
with jpaTemplate.flush();
In response to Sajids' comment: With Spring you can configure a transaction manager that supports both JPA and JDBC like this:
<tx:annotation-driven transaction-manager="transactionManager" />
<!-- Transaction manager -->
<bean id="transactionManager" class="org.springframework.orm.jpa
.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
and Annotation-Driven version
@Bean
public JpaTransactionManager transactionManager(EntityManagerFactory emf) {
JpaTransactionManager jpaTransactionManager = new JpaTransactionManager();
jpaTransactionManager.setEntityManagerFactory(emf);
return jpaTransactionManager;
}
In order to make it work, the JDBC queries must be executed with the JdbcTemplate or the SimpleJdbcTemplate class. In your case with the DAO that extends the SimpleJdbcDaoSupport, you should use the getSimpleJdbcTemplate(..) method.
And finally to let two DAO methods participate in the same transaction, call both DAO methods from a service class metho annotated with @Transactional. With the <tx:annotation-driven>
element in your config, Spring will handle the transaction for you with the given transaction manager.
On the business layer:
public class ServiceClass {..
@Transactional
public void updateDatabase(..) {
jpaDao.remove(..);
jdbcDao.insert(..);
}
}
Edit 2: Then something is wrong. It works for me exactly as specified in the Javadoc. Does your entity manager has a datasource property like my bean below? It will only work as long you're injecting the same datasource into the entity manager and your extended JpaDaoSupport classes.
<bean id="entityManagerFactoryWithExternalDataSoure" primary="true"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor
.HibernateJpaVendorAdapter" />
</property>
<property name="jpaProperties">
<value>
hibernate.format_sql=true
</value>
</property>
</bean>