Python/PIL Resize all images in a folder

Question

I have the following code that I thought would resize the images in the specified path But when I run it, nothing works and yet python doesn\'t throw any error so I don\'t

Answer 1

For those that are on Windows:

from PIL import Image
import glob

image_list = []
resized_images = []

for filename in glob.glob('YOURPATH\\*.jpg'):
    print(filename)
    img = Image.open(filename)
    image_list.append(img)

for image in image_list:
    image = image.resize((224, 224))
    resized_images.append(image)

for (i, new) in enumerate(resized_images):
    new.save('{}{}{}'.format('YOURPATH\\', i+1, '.jpg'))

Answer 2

Heavily borrowed the code from @Sanjar Stone. This code work well in Windows OS. Can be used to bulky resize the images and assembly back to its corresponding subdirectory.

Original folder with it subdir:
..\DATA\ORI-DIR
├─Apolo
├─Bailey
├─Bandit
├─Bella

New folder with its subdir:

..\DATA\NEW-RESIZED-DIR
├─Apolo
├─Bailey
├─Bandit
├─Bella

Gist link: https://gist.github.com/justudin/2c1075cc4fd4424cb8ba703a2527958b

from PIL import Image
import glob
import os

# new folder path (may need to alter for Windows OS)
# change path to your path
ORI_PATH = '..\DATA\ORI-DIR'
NEW_SIZE = 224
PATH = '..\DATA\NEW-RESIZED-DIR' #the path where to save resized images

# create new folder
if not os.path.exists(PATH):
    os.makedirs(PATH)

# loop over existing images and resize
# change path to your path
for filename in glob.glob(ORI_PATH+'**/*.jpg'): #path of raw images with is subdirectory
    img = Image.open(filename).resize((NEW_SIZE,NEW_SIZE))
    
    # get the original location and find its subdir
    loc = os.path.split(filename)[0]
    subdir = loc.split('\\')[1]
    
    # assembly with its full new directory
    fullnew_subdir = PATH+"/"+subdir
    name = os.path.split(filename)[1]
    
    # check if the subdir is already created or not
    if not os.path.exists(fullnew_subdir):
        os.makedirs(fullnew_subdir)
    
    # save resized images to new folder with existing filename
    img.save('{}{}{}'.format(fullnew_subdir,'/',name))