using predict with a list of lm() objects

Question

I have data which I regularly run regressions on. Each \"chunk\" of data gets fit a different regression. Each state, for example, might have a different function that expla

Answer 1

A solution with just base R. The format of the output is different, but all the values are right there.

models <- lapply(split(myData, myData$state), 'lm', formula = value ~ year)
pred4  <- mapply('predict', models, split(newData, newData$state))

Answer 2

You need to use mdply to supply both the model and the data to each function call:

dataList <- dlply(newData, "state")

preds <- mdply(cbind(mod = modelList, df = dataList), function(mod, df) {
  mutate(df, pred = predict(mod, newdata = df))
})

Answer 3

I take it the hard part is matching each state in newData to the corresponding model.

Something like this perhaps?

predList <- dlply(newData, "state", function(x) {
  predict(modelList[[as.character(min(x$state))]], x) 
})

Here I used a "hacky" way of extracting the corresponding state model: as.character(min(x$state))

...There is probably a better way?

Output:

> predList[1:2]
$`50`
       1        2        3        4        5        6        7        8        9       10       11 
5176.326 5274.907 5373.487 5472.068 5570.649 5669.229 5767.810 5866.390 5964.971 6063.551 6162.132 

$`51`
      12       13       14       15       16       17       18       19       20       21       22 
5514.825 5626.160 5737.496 5848.832 5960.167 6071.503 6182.838 6294.174 6405.510 6516.845 6628.181

Or, if you want a data.frame as output:

predData <- ddply(newData, "state", function(x) {
  y <-predict(modelList[[as.character(min(x$state))]], x)
  data.frame(id=names(y), value=c(y))
})

Output:

head(predData)
  state id    value
1    50  1 5176.326
2    50  2 5274.907
3    50  3 5373.487
4    50  4 5472.068
5    50  5 5570.649
6    50  6 5669.229

Answer 4

What is wrong with

lapply(modelList, predict, newData)

?

EDIT:

Thanks for explaining what is wrong with that. How about:

newData <- data.frame(year)
ldply(modelList, function(model) {
  data.frame(newData, predict=predict(model, newData))
})

Iterate over the models, and apply the new data (which is the same for each state since you just did an expand.grid to create it).

EDIT 2:

If newData does not have the same values for year for every state as in the example, a more general approach can be used. Note that this uses the original definition of newData, not the one in the first edit.

ldply(state, function(s) {
  nd <- newData[newData$state==s,]
  data.frame(nd, predict=predict(modelList[[as.character(s)]], nd))
})

First 15 lines of this output:

   year state  predict
1    50    50 5176.326
2    51    50 5274.907
3    52    50 5373.487
4    53    50 5472.068
5    54    50 5570.649
6    55    50 5669.229
7    56    50 5767.810
8    57    50 5866.390
9    58    50 5964.971
10   59    50 6063.551
11   60    50 6162.132
12   50    51 5514.825
13   51    51 5626.160
14   52    51 5737.496
15   53    51 5848.832

Answer 5

Here's my attempt:

predNaughty <- ddply(newData, "state", transform,
  value=predict(modelList[[paste(piece$state[1])]], newdata=piece))
head(predNaughty)
#   year state    value
# 1   50    50 5176.326
# 2   51    50 5274.907
# 3   52    50 5373.487
# 4   53    50 5472.068
# 5   54    50 5570.649
# 6   55    50 5669.229
predDiggsApproved <- ddply(newData, "state", function(x)
  transform(x, value=predict(modelList[[paste(x$state[1])]], newdata=x)))
head(predDiggsApproved)
#   year state    value
# 1   50    50 5176.326
# 2   51    50 5274.907
# 3   52    50 5373.487
# 4   53    50 5472.068
# 5   54    50 5570.649
# 6   55    50 5669.229

JD Long edit

I was inspired enough to work out an adply() option:

pred3 <- adply(newData, 1,  function(x)
    predict(modelList[[paste(x$state)]], newdata=x))
head(pred3)
#   year state        1
# 1   50    50 5176.326
# 2   51    50 5274.907
# 3   52    50 5373.487
# 4   53    50 5472.068
# 5   54    50 5570.649
# 6   55    50 5669.229

Answer 6

Maybe I'm missing something, but I believe lmList is the ideal tool here,

library(nlme)
ll = lmList(value ~ year | state, data=myData)
predict(ll, newData)


## Or, to show that it produces the same results as the other proposed methods...
newData[["value"]] <- predict(ll, newData)
head(newData)
#   year state    value
# 1   50    50 5176.326
# 2   51    50 5274.907
# 3   52    50 5373.487
# 4   53    50 5472.068
# 5   54    50 5570.649
# 6   55    50 5669.229