Get everything after and before certain character in SQL Server

Question

I got the following entry in my database:

images/test.jpg

I want to trim the entry so I get: test

So basically, I want

Answer 1

----select characters before / including /

select SUBSTRING ('abcde/wxyz',0,CHARINDEX('/','abcde/wxyz')+1)

--select characters after / including /

select SUBSTRING('abcde/wxyz',CHARINDEX('/','abcde/wxyz'),LEN('abcde/wxyz')) 

Answer 2

SELECT SUBSTRING('ravi1234@gmail.com',1,(CHARINDEX('@','ravi1234@gmail.com')-1)) Before, RIGHT('ravi123@gmail.com',(CHARINDEX('@','ravi123@gmail.com')+1)) After

Answer 3

If you want to get this out of your table using SQL, take a look at the following functions that will help you: SUBSTRING and CHARINDEX. You can use those to trim your entries.

A possible query will look like this (where col is the name of the column that contains your image directories:

SELECT SUBSTRING(col, LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) + 1, 
    LEN(col) - LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) - LEN(SUBSTRING(
    col, CHARINDEX ('.', col), LEN(col))));

Bit of an ugly beast. It also depends on the standard format of 'dir/name.ext'.

Edit:
This one (inspired by praveen) is more generic and deals with extensions of different length:

SELECT SUBSTRING(col, LEN(LEFT(col, CHARINDEX ('/', col))) + 1, LEN(col) - LEN(LEFT(col, 
    CHARINDEX ('/', col))) - LEN(RIGHT(col, LEN(col) - CHARINDEX ('.', col))) - 1);

Answer 4

I have made a method which is much more general :

so :

DECLARE @a NVARCHAR(MAX)='images/test.jpg';


 --Touch here
DECLARE @keysValueToSearch NVARCHAR(4000) = '/'
DECLARE @untilThisCharAppears NVARCHAR(4000) = '.'
DECLARE @keysValueToSearchPattern NVARCHAR(4000) = '%' + @keysValueToSearch + '%'


 --Nothing to touch here     
SELECT SUBSTRING(
           @a,
           PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch),
           CHARINDEX(
               @untilThisCharAppears,
               @a,
               PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch)
           ) -(PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch))
       )

Answer 5

I know this has been a while.. but here is an idea

declare @test varchar(25) = 'images/test.jpg'

select
 @test as column_name
 , parsename(replace(@test,'/','.'),1) as jpg
 ,parsename(replace(@test,'/','.'),2) as test
  ,parsename(replace(@test,'/','.'),3) as images

Answer 6

I got some invalid length errors. So i made this function, this should not give any length problems. Also when you do not find the searched text it will return a NULL.

CREATE FUNCTION [FN].[SearchTextGetBetweenStartAndStop](@string varchar(max),@SearchStringToStart varchar(max),@SearchStringToStop varchar(max))

RETURNS varchar(max)

BEGIN


    SET @string =    CASE 
                         WHEN CHARINDEX(@SearchStringToStart,@string) = 0
                           OR CHARINDEX(@SearchStringToStop,RIGHT(@string,LEN(@string) - CHARINDEX(@SearchStringToStart,@string) + 1 - LEN(@SearchStringToStart))) = 0
                         THEN NULL
                         ELSE SUBSTRING(@string
                                       ,CHARINDEX(@SearchStringToStart,@string) + LEN(@SearchStringToStart) + 1
                                       ,(CHARINDEX(@SearchStringToStop,RIGHT(@string,LEN(@string) - CHARINDEX(@SearchStringToStart,@string) + 1 - LEN(@SearchStringToStart)))-2)     
                                       )
                     END


    RETURN @string

END