How to create a function in SQL Server

Question

Please help me, how to filter words in SQL using a function?

I\'m having a hard time if I explain it so I\'m giving example:

ID       |       Websit         


        

Answer 1

This one get everything between the "." characters. Please note this won't work for more complex URLs like "www.somesite.co.uk" Ideally the function would check for how many instances of the "." character and choose the substring accordingly.

CREATE FUNCTION dbo.GetURL (@URL VARCHAR(250))
RETURNS VARCHAR(250)
AS BEGIN
    DECLARE @Work VARCHAR(250)

    SET @Work = @URL

    SET @Work = SUBSTRING(@work, CHARINDEX('.', @work) + 1, LEN(@work))   
    SET @Work = SUBSTRING(@work, 0, CHARINDEX('.', @work))

    --Alternate:
    --SET @Work = SUBSTRING(@work, CHARINDEX('.', @work) + 1, CHARINDEX('.', @work) + 1)   

    RETURN @work
END

Answer 2

How about this?

CREATE FUNCTION dbo.StripWWWandCom (@input VARCHAR(250))
RETURNS VARCHAR(250)
AS BEGIN
    DECLARE @Work VARCHAR(250)

    SET @Work = @Input

    SET @Work = REPLACE(@Work, 'www.', '')
    SET @Work = REPLACE(@Work, '.com', '')

    RETURN @work
END

and then use:

SELECT ID, dbo.StripWWWandCom (WebsiteName)
FROM dbo.YourTable .....

Of course, this is severely limited in that it will only strip www. at the beginning and .com at the end - nothing else (so it won't work on other host machine names like smtp.yahoo.com and other internet domains such as .org, .edu, .de and etc.)

Answer 3

You can use stuff in place of replace for avoiding the bug that Hamlet Hakobyan has mentioned

CREATE FUNCTION dbo.StripWWWandCom (@input VARCHAR(250)) 
RETURNS VARCHAR(250) 
AS BEGIN
   DECLARE @Work VARCHAR(250)
   SET @Work = @Input

   --SET @Work = REPLACE(@Work, 'www.', '')
   SET @Work = Stuff(@Work,1,4, '')
   SET @Work = REPLACE(@Work, '.com', '')

   RETURN @work 
END

Answer 4

This will work for most of the website names :

SELECT ID, REVERSE(PARSENAME(REVERSE(WebsiteName), 2)) FROM dbo.YourTable .....

Answer 5

I can give a small hack, you can use T-SQL function. Try this:

SELECT ID, PARSENAME(WebsiteName, 2)
FROM dbo.YourTable .....