read file in classpath

Question

Here is what I want to do and I am wondering if there is any Spring classes that will help with implementing. I don\'t have to use spring for this particular problem, I\'m

Answer 1

Change . to / as the path separator and use getResourceAsStream:

reader = new BufferedReader(new InputStreamReader(
    getClass().getClassLoader().getResourceAsStream(
        "com/company/app/dao/sql/SqlQueryFile.sql")));

or

reader = new BufferedReader(new InputStreamReader(
    getClass().getResourceAsStream(
        "/com/company/app/dao/sql/SqlQueryFile.sql")));

Note the leading slash when using Class.getResourceAsStream() vs ClassLoader.getResourceAsStream. getSystemResourceAsStream uses the system classloader which isn't what you want.

I suspect that using slashes instead of dots would work for ClassPathResource too.

Answer 2

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;

public class readFile {
    /**
     * feel free to make any modification I have have been here so I feel you
     * 
     * @param args
     * @throws InterruptedException
     */
    public static void main(String[] args) throws InterruptedException {
        File dir = new File(".");// read file from same directory as source //
        if (dir.isDirectory()) {
            File[] files = dir.listFiles();
            for (File file : files) {
                // if you wanna read file name with txt files
                if (file.getName().contains("txt")) {
                    System.out.println(file.getName());
                }

                // if you want to open text file and read each line then
                if (file.getName().contains("txt")) {
                    try {
                        // FileReader reads text files in the default encoding.
                        FileReader fileReader = new FileReader(
                                file.getAbsolutePath());
                        // Always wrap FileReader in BufferedReader.
                        BufferedReader bufferedReader = new BufferedReader(
                                fileReader);
                        String line;
                        // get file details and get info you need.
                        while ((line = bufferedReader.readLine()) != null) {
                            System.out.println(line);
                            // here you can say...
                            // System.out.println(line.substring(0, 10)); this
                            // prints from 0 to 10 indext
                        }
                    } catch (FileNotFoundException ex) {
                        System.out.println("Unable to open file '"
                                + file.getName() + "'");
                    } catch (IOException ex) {
                        System.out.println("Error reading file '"
                                + file.getName() + "'");
                        // Or we could just do this:
                        ex.printStackTrace();
                    }
                }
            }
        }

    }`enter code here`

}

Answer 3

Try getting Spring to inject it, assuming you're using Spring as a dependency-injection framework.

In your class, do something like this:

public void setSqlResource(Resource sqlResource) {
    this.sqlResource = sqlResource;
}

And then in your application context file, in the bean definition, just set a property:

<bean id="someBean" class="...">
    <property name="sqlResource" value="classpath:com/somecompany/sql/sql.txt" />
</bean>

And Spring should be clever enough to load up the file from the classpath and give it to your bean as a resource.

You could also look into PropertyPlaceholderConfigurer, and store all your SQL in property files and just inject each one separately where needed. There are lots of options.