Integer to IP Address - C

Question

I\'m preparing for a quiz, and I have a strong suspicion I may be tasked with implementing such a function. Basically, given an IP address in network notation, how can we ge

Answer 1

#include "stdio.h"

void print_ip(int ip) {
   unsigned char bytes[4];
   int i;
   for(i=0; i<4; i++) {
      bytes[i] = (ip >> i*8) & 0xFF;
   }
   printf("%d.%d.%d.%d\n", bytes[3], bytes[2], bytes[1], bytes[0]);
}

int main() {
   int ip = 0xDEADBEEF;
   print_ip(ip);   
}

Answer 2

From string to int and back

const char * s_ip = "192.168.0.5";
unsigned int ip;
unsigned char * c_ip = (unsigned char *)&ip;
sscanf(s_ip, "%hhu.%hhu.%hhu.%hhu", &c_ip[3], &c_ip[2], &c_ip[1], &c_ip[0]);
printf("%u.%u.%u.%u", ((ip & 0xff000000) >> 24), ((ip & 0x00ff0000) >> 16), ((ip & 0x0000ff00) >> 8), (ip & 0x000000ff));

%hhu instructs sscanf to read into unsigned char pointer; (Reading small int with scanf)

---

inet_ntoa from glibc

char *
inet_ntoa (struct in_addr in)
{
unsigned char *bytes = (unsigned char *) ∈
__snprintf (buffer, sizeof (buffer), "%d.%d.%d.%d",
bytes[0], bytes[1], bytes[2], bytes[3]);
return buffer;
}

Answer 3

Hint: break up the 32-bit integer to 4 8-bit integers, and print them out.

Something along the lines of this (not compiled, YMMV):

int i = 0xDEADBEEF; // some 32-bit integer
printf("%i.%i.%i.%i",
          (i >> 24) & 0xFF,
          (i >> 16) & 0xFF,
          (i >> 8) & 0xFF,
          i & 0xFF);