I have a gradle build setup at the beginning of which I want to execute a shellscript in a subdirectory that prepares my environment.
task build << {
unfortunately options with commandLine not worked for me in any way and my friend find other way with executable
executable "./myScript.sh"
and full task would be
task startScript() {
doLast {
exec {
executable "./myScript.sh"
}
}
}
I copied my shell scipt to /usr/local/bin
with +x
permission and used it as just another command:
commandLine 'my_script.sh'
A more generic way of writing the exec task, but portable for Windows/Linux, if you are invoking a command file on the PATH:
task myPrebuildTask(type: Exec) {
workingDir "$projectDir/mySubDir"
if (System.getProperty('os.name').toLowerCase(Locale.ROOT).contains('windows')) {
commandLine 'cmd', '/c', 'mycommand'
} else {
commandLine 'sh', '-c', 'mycommand'
}
}
This doesn't directly address the use case for the OP (since there is script file in the working directory), but the title of the question is more generic (and drew me here), so it could help someone maybe.
This works for me in my Android project
preBuild.doFirst {
println("Executing myScript")
def proc = "mySubDir/myScript.sh".execute()
proc.waitForProcessOutput(System.out, System.err)
}
See here for explanation: How to make System command calls in Java/Groovy?
for kotlin gradle you can use
Runtime.getRuntime().exec("./my_script.sh")
use
commandLine 'sh', './myScript.sh'
your script itself is not a program itself, that's why you have to declare 'sh' as the program and the path to your script as an argument.