total size of group of files selected with 'find'

Question

For instance, I have a large filesystem that is filling up faster than I expected. So I look for what\'s being added:

find /rapidly_shrinking_drive/ -type f          


        

Answer 1

Recently i faced the same(almost) problem and i came up with this solution.

find $path -type f -printf '%s '

It'll show files sizes in bytes, from man find:

-printf format
    True; print format on the standard output, interpreting `\' escapes and `%' directives.  Field widths and precisions can be spec‐
    ified as with the `printf' C function.  Please note that many of the fields are printed as %s rather than %d, and this  may  mean
    that  flags  don't  work as you might expect.  This also means that the `-' flag does work (it forces fields to be left-aligned).
    Unlike -print, -printf does not add a newline at the end of the string.
    ...
    %s  File's size in bytes.
    ...

And to get a total i used this:

echo $[ $(find $path -type f -printf %s+)0] #b
echo $[($(find $path -type f -printf %s+)0)/1024] #Kb
echo $[($(find $path -type f -printf %s+)0)/1024/1024] #Mb
echo $[($(find $path -type f -printf %s+)0)/1024/1024/1024] #Gb

Answer 2

Darn, Stephan202 is right. I didn't think about du -s (summarize), so instead I used awk:

find rapidly_shrinking_drive/ -name "offender1" -mtime -1 | du | awk '{total+=$1} END{print total}'

I like the other answer better though, and it's almost certainly more efficient.

Answer 3

I have tried all this commands but no luck. So I have found this one that gives me an answer:

find . -type f -mtime -30 -exec ls -l {} \; | awk '{ s+=$5 } END { print s }'

Answer 4

You could also use ls -l to find their size, then awk to extract the size:

find /rapidly_shrinking_drive/ -name "offender1" -mtime -1 | ls -l | awk '{print $5}' | sum

Answer 5

The command du tells you about disk usage. Example usage for your specific case:

find rapidly_shrinking_drive/ -name "offender1" -mtime -1 -print0 | du --files0-from=- -hc | tail -n1

(Previously I wrote du -hs, but on my machine that appears to disregard find's input and instead summarises the size of the cwd.)

Answer 6

with GNU find,

 find /path -name "offender" -printf "%s\n" | awk '{t+=$1}END{print t}'