How to get NSDate day, month and year in integer format?

Question

I want to get the day, month and year components of NSDate in integer form i.e. if the date is 1/2/1988 then I should get 1, 2 and 1988 separately as an integer

Answer 1

Here you are,

NSDate *currentDate = [NSDate date];
NSCalendar* calendar = [NSCalendar currentCalendar];
NSDateComponents* components = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDay fromDate:currentDate]; // Get necessary date components

 [components month]; //gives you month
 [components day]; //gives you day
 [components year]; // gives you year

You can use NSDateComponents for that as above.

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Hope it helps.

Answer 2

Put it in an extension and live your life

Answer 3

Swift

let components = NSCalendar.currentCalendar().components([.Day, .Month, .Year], fromDate: self)
let day = components.day
let month = components.month
let year = components.year

For convenience you can put this in an NSDate extension and make it return a tuple:

extension NSDate: Comparable {

    var dayMonthYear: (Int, Int, Int) {
        let components = NSCalendar.currentCalendar().components([.Day, .Month, .Year], fromDate: self)
        return (components.day, components.month, components.year)
    }
}

Now you have to write only:

let (day, month, year) = date.dayMonthYear

If you wanted to e.g. get only the the year you can write:

let (_, _, year) = date.dayMonthYear